mysql에 netibank라는 데이타베이스를 생성하구 netibank데이타베이스 안에
user_info라는 테이블을 생성한 다음에 다음과 같이 코딩을 하구 실행시겼더니
다음과 같은 에러가 나더라구요
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Warning: Supplied argument is not a valid MySQL-Link resource in /mydir/web/mssql.php on line 6
 Warning: Supplied argument is not a valid MySQL-Link resource in /mydir/web/mssql.php on line 10
 Warning: Supplied argument is not a valid MySQL-Link resource in /mydir/web/mssql.php on line 11
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connection은 된건 같은데 netibank 라는 데이타베이스를 못찻는것 같습니다.
고수님들 제발 도와주세요..... (--)(__)(--)
 ================================= 소스 ======================================================
<?
echo("Database Connection.....................................................!<br>");
 $dbconn = mysql_connect("localhost","php","php99") || die("DB Server Connect Fail!");
 $status = mysql_select_db("netibank",$dbconn); <--- 6 line
 if(!$status)
{
$errNO = mysql_errno($dbconn); <-------------- 10 line
$errMSG = mysql_error($dbconn); <------------- 11 line
 echo("[Error Code] : $errNO : [Error Message] : $errMSG<br>");
echo("Server is netibank database connet fail!<br>");
exit;
}
 else
{
echo("netibank Database connet success!<br>");
}
$query = "select * from user_info";
$result = mysql_query($query,$dbconn); //->waring
 if(!$result)
{
$errNO = mysql_errno($dbconn); //->waring
$errMSG = mysql_error($dbcon); //->waring
 echo("[Error Code] : $errNO [Error Msg] : $errMSG");
exit;
}
  $fields = mysql_num_fields($result);
 echo("<table border=0 cellpaddin=10>");
echo("<tr>=n");
echo("<td width=100 bgcolor=pink align=center> FILD NAME</td>");
echo("<td width=100 bgcolor=pink align=center> FILD TYPE</td>");
echo("<td width=100 bgcolor=pink align=center> FILD SIZE</td>");
echo("<td width=100 bgcolor=pink align=center> FILD FLAGS</td>");
echo("<td width=100 bgcolor=pink align=center> TABLE NAME</td>");
echo("</tr>");
 for($irow = 0; $irow<$fields; $i++)
{
echo("<tr>");
 $field_name = mysql_field_name($result,$i);
$field_type = mysql_field_name($result,$i);
$field_len = mysql_field_name($result,$i);
$field_flags = mysql_field_name($result,$i);
$field_table = mysql_field_name($result,$i);
echo("<td bgcolor=lightyellow align=center>$field_name</td>");
echo("<td bgcolor=lightyellow align=center>$field_type</td>");
echo("<td bgcolor=lightyellow align=center>$field_len</td>");
echo("<td bgcolor=lightyellow align=center>$field_flags</td>");
echo("<td bgcolor=lightyellow align=center>$field_table</td>");
echo("</table>");
}
mssql_close($dbconn);