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mysql에 netibank라는 데이타베이스를 생성하구 netibank데이타베이스 안에 
user_info라는 테이블을 생성한 다음에 다음과 같이 코딩을 하구 실행시겼더니 
다음과 같은 에러가 나더라구요 
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Warning: Supplied argument is not a valid MySQL-Link resource in /mydir/web/mssql.php on line 6 
 Warning: Supplied argument is not a valid MySQL-Link resource in /mydir/web/mssql.php on line 10 
 Warning: Supplied argument is not a valid MySQL-Link resource in /mydir/web/mssql.php on line 11 
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connection은 된건 같은데 netibank 라는 데이타베이스를 못찻는것 같습니다. 
고수님들 제발 도와주세요..... (--)(__)(--) 
 ================================= 소스 ====================================================== 
<? 
echo("Database Connection.....................................................!<br>"); 
 $dbconn = mysql_connect("localhost","php","php99") || die("DB Server Connect Fail!"); 
 $status = mysql_select_db("netibank",$dbconn); <--- 6 line 
 if(!$status) 
{ 
$errNO = mysql_errno($dbconn); <-------------- 10 line 
$errMSG = mysql_error($dbconn); <------------- 11 line 
 echo("[Error Code] : $errNO : [Error Message] : $errMSG<br>"); 
echo("Server is netibank database connet fail!<br>"); 
exit; 
} 
 else 
{ 
echo("netibank Database connet success!<br>"); 
} 
$query = "select * from user_info"; 
$result = mysql_query($query,$dbconn); //->waring 
 if(!$result) 
{ 
$errNO = mysql_errno($dbconn); //->waring 
$errMSG = mysql_error($dbcon); //->waring 
 echo("[Error Code] : $errNO [Error Msg] : $errMSG"); 
exit; 
} 
  $fields = mysql_num_fields($result); 
 echo("<table border=0 cellpaddin=10>"); 
echo("<tr>=n"); 
echo("<td width=100 bgcolor=pink align=center> FILD NAME</td>"); 
echo("<td width=100 bgcolor=pink align=center> FILD TYPE</td>"); 
echo("<td width=100 bgcolor=pink align=center> FILD SIZE</td>"); 
echo("<td width=100 bgcolor=pink align=center> FILD FLAGS</td>"); 
echo("<td width=100 bgcolor=pink align=center> TABLE NAME</td>"); 
echo("</tr>"); 
 for($irow = 0; $irow<$fields; $i++) 
{ 
echo("<tr>"); 
 $field_name = mysql_field_name($result,$i); 
$field_type = mysql_field_name($result,$i); 
$field_len = mysql_field_name($result,$i); 
$field_flags = mysql_field_name($result,$i); 
$field_table = mysql_field_name($result,$i); 
echo("<td bgcolor=lightyellow align=center>$field_name</td>"); 
echo("<td bgcolor=lightyellow align=center>$field_type</td>"); 
echo("<td bgcolor=lightyellow align=center>$field_len</td>"); 
echo("<td bgcolor=lightyellow align=center>$field_flags</td>"); 
echo("<td bgcolor=lightyellow align=center>$field_table</td>"); 
echo("</table>"); 
} 
mssql_close($dbconn);