$out = getimagesize("http://www.hellophp.com/ifsnow/screen/bio.gif"); echo $out[0]; 이렇게 절대 url 로 하면 안돼나요?? Warning: Unable to open http://www.hellophp.com/ifsnow/screen/bio.gif 위 메세지가 자꾸 뜨네요..
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